2/5x^2+24=0

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Solution for 2/5x^2+24=0 equation: 



2/5x^2+24=0



Domain of the equation: 5x^2!=0

x^2!=0/5

x^2!=√0

x!=0

x∈R



We multiply all the terms by the denominator


24*5x^2+2=0

Wy multiply elements

120x^2+2=0

a = 120; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·120·2
Δ = -960
Delta is less than zero, so there is no solution for the equation

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